EN 1993 Bolt Group Capacity — Eccentric Load per Eurocode 3
Complete guide to bolt group analysis under eccentric loading per EN 1993-1-8:2005. Elastic (vector) and instantaneous center of rotation (ICR) methods for bolt groups subjected to combined shear and torsion/moment. Worked examples with M20 8.8 bolts.
Quick access: Bolt Bearing & Tearout → | Bolt Pretension → | Bolt Spacing →
Elastic (Vector) Method
The elastic method assumes linear-elastic behavior:
- The applied load P is resolved into direct shear plus moment about the bolt group centroid
- Direct shear per bolt: F_i = P / n (equal distribution)
- Torsional shear component: F_M,i = M × r_i / Σ(r_j²)
Where M = P × e (eccentric moment), n = number of bolts, r_i = distance from bolt to centroid.
For each bolt:
F_resultant,i = √((F_x + F_M,xi)² + (F_y + F_M,yi)²)
The design check: F_resultant,max ≤ F_b,Rd and F_resultant,max ≤ F_v,Rd.
Worked Example — 4-Bolt Bracket, M20 8.8
Geometry:
- 4 bolts in a 150 × 200 mm pattern (p₁ = 100 mm, p₂ = 100 mm)
- Bracket load: P = 100 kN at e = 200 mm eccentricity
- Bolt grade: M20 8.8 (F_v,Rd = 94.1 kN per bolt, F_b,Rd = 137.3 kN for 12 mm S355)
- d₀ = 22 mm
Centroid properties:
| Property | Value |
|---|---|
| Bolt group centroid | Centered |
| r_max (corner bolt) | √(50² + 50²) = 70.7 mm |
| Σ(r_j²) | 4 × (50² + 50²) = 20000 mm² |
| Direct shear per bolt (vertical) | 100 / 4 = 25.0 kN |
| Moment | 100 × 200 = 20000 kN·mm |
| Torsional shear at corner (horizontal) | 20000 × 50 / 20000 = 50.0 kN |
| Torsional shear at corner (vertical) | 20000 × 50 / 20000 = 50.0 kN |
Resultant at critical bolt (corner, vertical component):
F_resultant = √(50.0² + (25.0 + 50.0)²) = √(2500 + 5625) = 90.1 kN
Check:
- Shear: 90.1 kN ≤ 94.1 kN ✓ (F_v,Rd governs)
- Bearing: 90.1 kN ≤ 137.3 kN ✓
Utilization: 90.1 / 94.1 = 0.96 — OK, but close to capacity.
Instantaneous Center of Rotation (ICR) Method
For a more accurate (less conservative) analysis, the ICR method considers:
- The bolt group rotates about an instantaneous center (not the centroid)
- Bolt forces are proportional to distance from the ICR, but limited by bolt deformation capacity
- The ICR location is found iteratively by satisfying equilibrium
The ICR method typically gives 10-30% higher capacity than the elastic vector method for eccentric connections with significant rotation.
| Method | Max Bolt Force | Utilization | Conservatism |
|---|---|---|---|
| Elastic vector | 90.1 kN | 0.96 | Conservative |
| ICR method | ~78 kN | ~0.83 | More accurate |
Bolt Group Capacity Tables — M20 8.8 in S355 (12 mm plate)
4-Bolt Group (2×2), Vertical Load
| Eccentricity e (mm) | Elastic Capacity (kN) | ICR Capacity (kN) |
|---|---|---|
| 0 (concentric) | 376 | 376 |
| 50 | 240 | 275 |
| 100 | 160 | 190 |
| 150 | 120 | 145 |
| 200 | 96 | 120 |
| 300 | 68 | 88 |
6-Bolt Group (3×2), Vertical Load
| Eccentricity e (mm) | Elastic Capacity (kN) | ICR Capacity (kN) |
|---|---|---|
| 0 (concentric) | 564 | 564 |
| 100 | 300 | 360 |
| 200 | 184 | 228 |
| 300 | 130 | 164 |
Bolt Shear Resistance per EN 1993-1-8
Shear per Bolt (Threads in Shear Plane — Category A)
F_v,Rd = α_v × f_ub × A_s / γ_M2
Where α_v = 0.6 for 8.8 and 10.9, γ_M2 = 1.25.
Bearing per Bolt
F_b,Rd = (k₁ × α_b × f_u × d × t) / γ_M2
See the bearing and tearout guide for detailed factor calculations.
Design Applications
Common Design Scenarios
This reference covers structural design scenarios commonly encountered in structural steel design practice:
- Strength verification: Check member or connection capacity against factored loads per the applicable design code
- Serviceability checks: Verify deflections, vibrations, and other serviceability criteria
- Code compliance: Ensure design meets all provisions of the governing standard
- Connection detailing: Verify weld sizes, bolt quantities, and edge distances
Related Design Considerations
- System behavior: consider the interaction between members and connections
- Load paths: verify that forces can be transferred through the structure to the foundations
- Constructability: check that the design can be fabricated and erected practically
- Cost optimization: evaluate alternative sections or connection types for economy
Worked Example
Problem: Verify a typical steel member for the following conditions:
Typical span: 6.0 m | Load: service loads per applicable code | Section: common section in this category
Design Check:
- Determine governing load combination (LRFD or ASD per applicable code)
- Calculate maximum internal forces (moment, shear, axial)
- Compute nominal capacity per code provisions
- Apply resistance/safety factors
- Verify interaction if combined forces exist
Result: Use the results from the Steel Calculator tool to verify design adequacy.
Frequently Asked Questions
What Australian Standard governs structural steel design?
AS 4100-2020 (Steel Structures) is the primary standard for structural steel design in Australia. It covers all aspects of design including member capacity, connections, serviceability, and fire resistance. The standard uses a limit states design philosophy with resistance factors (φ) applied to nominal capacities. Companion standards include AS/NZS 3679.1 for hot-rolled sections, AS/NZS 1554 for welding, and AS/NZS 4600 for cold-formed steel.
What are the common steel grades used in Australian construction?
The most common steel grades for Australian construction are Grade 300 and Grade 350 per AS/NZS 3679.1. Grade 300 (minimum yield 300 MPa for sections > 12 mm thick) is the standard for general structural applications. Grade 350 (minimum yield 340 MPa for sections > 12 mm) is used where higher strength reduces weight. Grade 400 and Grade 450 are available for specialized applications requiring higher strength-to-weight ratios.
How does AS 4100 compare to AISC 360?
Both AS 4100 and AISC 360 use limit states design (LRFD) principles. Key differences include: AS 4100 uses a single "capacity factor" φ approach rather than separate φ for different failure modes; AS 4100 specifies distinct buckling curves for hot-rolled and welded sections; the moment capacity formula in AS 4100 uses αm factor directly rather than Cb; and AS 4100 has more detailed provisions for slender sections and combined actions. Despite philosophical differences, both codes produce similar results for typical members.
Frequently Asked Questions
Should I use the elastic or ICR method for bolt group design?
The elastic (vector) method is simpler, conservative, and acceptable for most connections per EN 1993-1-8. The ICR method gives a more accurate capacity assessment and is recommended for heavily loaded connections or when the elastic method gives utilization > 0.90. Some national annexes require the ICR method for specific connection types.
What is the maximum eccentricity for bolt groups in EN 1993?
EN 1993-1-8 does not specify a maximum eccentricity limit. However, as eccentricity increases, the connection becomes increasingly inefficient (one bolt carries most of the load). Practical limits are e ≤ 3 × bolt group depth. For larger eccentricities, consider a moment connection (end plate with stiffeners) instead of a simple bracket connection.
Related Pages
- Bolt Bearing & Tearout — Bearing per EN 1993-1-8 Clause 3.6
- Bolt Torque Chart — Torque-tension values
- Bolt Spacing — EN 1993-1-8 Table 3.3
- End Plate Connection — Moment connection design
- All European References
Educational reference only. Design per EN 1993-1-8:2005. γ_M2 = 1.25. Elastic method is conservative for eccentric groups. ICR method requires iterative analysis per EN 1993-1-8 Annex A. Results are PRELIMINARY — NOT FOR CONSTRUCTION without independent verification.
Design Resources
Calculator tools
- Bolt Torque Calculator
- Bolted Connection Calculator
- Splice Connection Calculator
- Steel Bolted Connection Calculator
Design guides