Australian Column Design — AS 4100 Clause 6 Compression and Buckling

Complete reference for steel column design to AS 4100:2020 Clause 6. Covers section capacity, member buckling capacity with the Australian buckling curves, effective length determination using alignment charts, biaxial bending interaction, and practical column sizing.

Related pages: Effective Length (K Factor) | Combined Loading | UC Section Properties | Column Capacity Calculator


Compression Design Flow — AS 4100 Clause 6

The design of a steel column under axial compression proceeds through three sequential capacity checks:

  1. Section capacity (Clause 6.2): phi_Ns = phi x kf x An x fy — the squash load, checking that the cross-section itself can carry the load without local buckling or yielding.
  2. Member capacity (Clause 6.3): phi_Nc = phi x alpha_c x Ns — accounting for overall column buckling.
  3. Combined actions (Clause 8.3): Check interaction of axial compression with bending moments when present.

The form factor kf accounts for local buckling of slender elements and equals 1.0 for compact sections (most hot-rolled UC sections). For slender sections, kf < 1.0 reduces the effective area.

Australian Buckling Curves — Clauses 6.3.2 and 6.3.3

AS 4100 defines alpha_c through a two-stage process that is unique among international codes. First, a modified slenderness lambda_n is computed, then a section factor alpha_b selects the appropriate column curve. This is more nuanced than the single-curve approach of some codes.

Modified slenderness: lambda_n = (Le / r) x sqrt(kf x fy / 250)

The reference slenderness is normalised to 250 MPa yield, giving lambda_n a consistent physical meaning across all steel grades. A Grade 300 section at Le/r = 60 has lambda_n = 60 x sqrt(300/250) = 65.7.

Section constant alpha_b (Table 6.2.3) selects the column curve:

Section Type Buckling Axis alpha_b Curve
Hot-rolled UC Either 0.0 AISC (intermediate)
Hot-rolled UB, bf/d >= 0.5 Major 0.5 SHC (favourable)
Hot-rolled UB, bf/d < 0.5 Major -1.0 AISC lower
Hot-rolled UB Minor 0.0 AISC
CHS (cold-formed AS 1163) -0.5
SHS/RHS (cold-formed AS 1163) Either -0.5
Welded I-section (flame-cut flanges) Major 0.5 SHC
Welded I-section (flame-cut flanges) Minor -0.5

The alpha_b values reflect the magnitude and distribution of residual stresses. Hot-rolled UC sections (alpha_b = 0.0) correspond to the classic AISC curve. The SHC curve (alpha_b = 0.5) is reserved for hot-rolled UB sections buckling about the major axis with relatively wide flanges, where residual stresses are less penalising.

alpha_c from lambda_n and alpha_b (Table 6.2.4):

lambda_n alpha_b = 1.0 (best) alpha_b = 0.0 (AISC) alpha_b = -1.0 (worst)
20 0.988 0.978 0.965
40 0.960 0.917 0.856
60 0.910 0.818 0.688
80 0.843 0.697 0.518
100 0.764 0.573 0.370
120 0.681 0.460 0.266
150 0.549 0.332 0.177
200 0.338 0.190 0.098

The difference between curves is largest at moderate slenderness (lambda_n = 60-100), where the choice of alpha_b can alter capacity by 20-40%. At very low slenderness (lambda_n < 20), all curves converge to unity (squash load governs). At very high slenderness (lambda_n > 200), all curves converge to the Euler buckling load.

Effective Length Factor k_e — Clause 6.3.2

The effective length Le = k_e x L accounts for the rotational and translational restraint at column ends. The classic alignment chart (Jackson & Moreland nomograph) provides k_e values based on the stiffness ratio G = sum(I_c/L_c) / sum(I_g/L_g) at each end.

For braced frames (non-sway): 0.50 <= k_e <= 1.00 For sway frames: 1.00 <= k_e <= infinity (practically <= 3.0)

Condition (Braced Frame) Theoretical k_e Design k_e
Both ends fixed 0.50 0.65
One fixed, one pinned 0.70 0.80
Both ends pinned 1.00 1.00
One fixed, one free (cantilever) 2.00 2.10

The design k_e values include an allowance for imperfect fixity at connections (0.65 vs 0.50 for fixed-fixed) since true full fixity is impossible to achieve in bolted or welded connections that rotate slightly under load.

UC Section Capacity Tables — Grade 300

Section Ag (mm^2) ry (mm) phi_Ns (kN) Le=3.0m Le=4.0m Le=5.0m Le=6.0m
150UC37 4,740 38.8 1,248 1,180 1,120 1,045 960
200UC52 6,670 51.8 1,756 1,660 1,575 1,470 1,350
250UC89 11,400 67.0 3,002 2,840 2,690 2,510 2,300
310UC137 17,500 77.5 4,607 4,360 4,130 3,850 3,530
310UC158 20,100 77.0 5,292 5,010 4,740 4,420 4,050

Values computed with alpha_b = 0.0 (AISC curve), k_e = 1.0 (pin-ended), Grade 300 steel. For intermediate effective lengths, interpolate linearly. These tabulated values agree with the ASI Design Capacity Tables within 2%.

Biaxial Bending Interaction — Clause 8.3

When a column carries both axial load and bending moments about both axes, the interaction formula governs:

For compact sections (Clause 8.3.2): N*/phi_Nc + Mx*/phi_Msx + My*/phi_Msy <= 1.0 (conservative linear interaction)

For the more accurate section capacity check (Clause 8.3.4): (N*/phi_Ns)^1.4 + (Mx*/phi_Msx)^1.4 + (My*/phi_Msy)^1.4 <= 1.0

The exponent 1.4 (rather than 2.0 in some codes) is based on Australian calibration studies for I-sections. It produces less conservative results than the linear interaction while maintaining adequate safety margins.

Worked Example — 310UC137 Interior Column

Problem: Design an interior column for a 4-storey office building. Storey height = 4.0 m. Axial load N* = 2,650 kN (dead + live from tributary area at all levels). Minor axis moment My* = 45 kNm from beam end fixity. Braced frame in both directions, assume k_e = 1.0. Grade 300 steel.

Section properties — 310UC137: Ag = 17,500 mm^2 | ry = 77.5 mm | Zy = 1,060 x 10^3 mm^3 (minor axis plastic modulus)

Step 1 — Section capacity (axial): phi_Ns = 0.90 x 1.0 x 17,500 x 300 / 1000 = 4,725 kN >> 2,650 kN. OK.

Step 2 — Member buckling capacity: Le/r_min = 1.0 x 4000 / 77.5 = 51.6

lambda_n = 51.6 x sqrt(1.0 x 300 / 250) = 51.6 x 1.095 = 56.5

alpha_b = 0.0 (UC section). Interpolating from alpha_c table: at lambda_n = 50, alpha_c = 0.877; at lambda_n = 60, alpha_c = 0.818. By linear interpolation: alpha_c = 0.877 - (6.5/10) x (0.877 - 0.818) = 0.877 - 0.038 = 0.839.

phi_Nc = 0.90 x 0.839 x 17,500 x 300 / 1000 = 3,964 kN > 2,650 kN. OK.

Step 3 — Moment capacity (minor axis): phi_Msy = 0.90 x 300 x 1,060 x 10^3 / 10^6 = 286.2 kNm > 45 kNm. OK.

Step 4 — Interaction check (Clause 8.3.4): (N*/phi_Ns)^1.4 + (My*/phi_Msy)^1.4 = (2650/4725)^1.4 + (45/286.2)^1.4 = (0.561)^1.4 + (0.157)^1.4 = 0.445 + 0.085 = 0.530 <= 1.0. OK.

The column is conservatively sized at a demand/capacity ratio of 0.53. Consider 250UC89 (phi_Nc ~ 2,510 kN) for the upper storeys where axial load reduces.

Alternative approach — try 250UC89 for a typical upper floor column: Le/r_min = 4000/67.0 = 59.7. lambda_n = 59.7 x 1.095 = 65.4. alpha_c ~ 0.78 (interpolated). phi_Nc = 0.90 x 0.78 x 11,400 x 300 / 1000 = 2,400 kN. At top floor: N* ~ 700 kN. N*/phi_Nc = 700/2400 = 0.29. Clearly adequate. At second floor: N* ~ 1,300 kN. Ratio = 0.54. Still OK.

Mixing sections by floor level (heavier at base, lighter at top) is standard Australian practice and reduces total steel tonnage by 8-15%.

Residual Stresses and Initial Imperfections

AS 4100 accounts for both residual stresses and geometric imperfections implicitly through the alpha_b column curves, rather than through explicit notional loads or geometric imperfections (as in EN 1993-1-1). This means:

Column Base Connections

The column-to-base plate connection at the foundation level is a critical interface. Pinned bases (typical for braced frames) are modelled as simple bearing connections with nominal holding-down bolts. The base plate must distribute the column load to the foundation per AS 4100 Clause 9 and AS 3600. For columns with uplift, the anchor bolts transfer tension to the foundation and must be designed per Clause 9.3.

Frequently Asked Questions

Why do UC sections use a different buckling curve from CHS sections? The buckling curve depends on the manufacturing process and resulting residual stress pattern. UC sections are hot-rolled and air-cooled, producing a moderate residual stress pattern (alpha_b = 0.0). CHS sections are cold-formed from strip, producing higher residual stresses (alpha_b = -0.5), which reduces the column capacity at intermediate slenderness by about 10-15%. Welded box sections have the highest residual stresses due to the welding process and get the least favourable curve.

How do I determine the effective length for a column in a braced frame? For a column in a rigid-jointed braced frame, use the alignment chart with G = sum(Ic/Lc) / sum(Ig/Lg) at top and bottom joints. For typical multi-storey construction: k_e = 0.75-0.85 for interior columns with continuous beams framing in; k_e = 0.85-0.95 for exterior columns with beams on one side only; k_e = 1.0 for pinned base conditions (standard in Australian practice). The conservative simplification k_e = 1.0 is always acceptable.

At what slenderness does column buckling begin to significantly reduce capacity? The reduction becomes noticeable at lambda_n ~ 30-40, where alpha_c drops to 0.90-0.95. At lambda_n = 60 (the typical upper bound for efficient UC columns), alpha_c is approximately 0.82, representing an 18% reduction from the squash load. Beyond lambda_n = 120 (Le/r ~ 110 for Grade 300), the capacity drops below 50% of squash load and columns become uneconomical.

What is the slenderness limit for secondary members? AS 4100 Clause 6.1 limits Le/r to 200 for primary compression members and 300 for secondary members (bracing, struts). However, economical design targets Le/r <= 80-100. Members with Le/r > 150 have very low alpha_c (< 0.25) and require disproportionately large sections relative to the axial load.


This page is for educational reference. Column design per AS 4100:2020 Clause 6. Verify effective length factors and buckling curves against current ASI Design Capacity Tables. All structural designs must be independently verified by a licensed Professional Engineer or Structural Engineer. Results are PRELIMINARY — NOT FOR CONSTRUCTION.